Physics · Forces & momentum

Resultant force calculator

Add two, three or four forces in a plane. Enter each magnitude and counterclockwise angle from +x; inspect the resultant, its direction and signed components.

Created v1.0

By Thibaut Grzelak, Mechanical Analysis Engineer

Forces & momentum
01Calculation inputsR = √(ΣF_x² + ΣF_y²)
Vectors originate at the same point; the dark resultant uses the same scale. Angles turn counterclockwise from +x.
Magnitude ≥ 0; enter its angle separately.
Counterclockwise from the positive x axis.
Magnitude ≥ 0; enter its angle separately.
Counterclockwise from the positive x axis.
Magnitude ≥ 0; enter its angle separately.
Counterclockwise from the positive x axis.
Magnitude ≥ 0; enter its angle separately.
Counterclockwise from the positive x axis.
02

Results

Direction from +x
—

Signed angle from −180° to 180°. Indeterminate at zero resultant (hidden).

Horizontal component
—

Positive toward +x.

Vertical component
—

Positive toward +y.

Relation and numerical substitutionR = √(ΣF_x² + ΣF_y²)

—

Concurrent forces or a translational force balance in two dimensions. All angles share the same Cartesian reference.

01Formulas and symbols

Formulas used

ΣF_xΣF_x = F1 × cos(θ1) + F2 × cos(θ2)Positive toward +x.
ΣF_yΣF_y = F1 × sin(θ1) + F2 × sin(θ2)Positive toward +y.
ΣF_xΣF_x = F1 × cos(θ1) + F2 × cos(θ2) + F3 × cos(θ3)Positive toward +x.
ΣF_yΣF_y = F1 × sin(θ1) + F2 × sin(θ2) + F3 × sin(θ3)Positive toward +y.
ΣF_xΣF_x = F1 × cos(θ1) + F2 × cos(θ2) + F3 × cos(θ3) + F4 × cos(θ4)Positive toward +x.
ΣF_yΣF_y = F1 × sin(θ1) + F2 × sin(θ2) + F3 × sin(θ3) + F4 × sin(θ4)Positive toward +y.
RR = √(ΣF_x² + ΣF_y²)Magnitude of the vector sum, not the sum of magnitudes.
θ_Rθ_R = atan2(ΣF_y, ΣF_x)Signed angle from −180° to 180°. Indeterminate at zero resultant (hidden).
02Assumptions and limits

Scope of validity

  • Concurrent forces or a translational force balance in two dimensions. All angles share the same Cartesian reference.
03Validation example

Reference numerical case

  1. 30 N at 0° plus 40 N at 90° gives ΣFx = 30 N, ΣFy = 40 N, R = 50 N and θR = 53.1301°.
04References

Technical references

  1. University Physics 1, §2.2 Vector components — OpenStax

FAQ

Can I enter negative force magnitudes?

Use a nonnegative magnitude and reverse the direction by 180°. Components may be negative.

Does R = 0 imply complete static equilibrium?

Only translational force balance. Rotational equilibrium also requires the sum of moments to vanish.

05Model and conventions

Add two, three or four forces in a plane. Enter each magnitude and counterclockwise angle from +x; inspect the resultant, its direction and signed components.

06Limits of this model

This does not calculate moments or the line of action of nonconcurrent loads. Tiny components at floating-point round-off scale are treated as zero.

07Common mistakes

Do not add magnitudes unless all forces share a direction. A zero resultant has no defined angle: its direction is deliberately omitted.