Fluid mechanics · Hydraulics

Pressure, force and area

Choose the unknown quantity. The relation F = P·A is applied in coherent SI units.

Created v1.0

By Thibaut Grzelak, Mechanical Analysis Engineer

Hydraulics
01Calculation inputsF = P · A
PAF
Input identificationPressure P acts on effective area A to produce force F.
02

Results

Force
—

Theoretical force.

Effective area
—

Required area.

Relation and numerical substitutionF = p · A

—

Uniform pressure. Static operation. Friction and back pressure ignored.

01Formulas and symbols

Formulas used

Fp · ATheoretical force
pF / APressure
AF / pEffective area
02Assumptions and limits

Scope of validity

  • Uniform pressure.
  • Static operation.
  • Friction and back pressure ignored.
03Validation example

Reference numerical case

  1. p = 100 bar and A = 10 cm².
  2. F = 10 kN.
04References

Technical references

  1. OpenStax — Pascal’s principle and hydraulics.
  2. BIPM — SI units; 1 Pa = 1 N/m².