Fluid mechanics · Piping and pressure

Thin-wall pipe stresses under pressure

Estimate membrane stresses caused by internal pressure and compare their magnitude with an allowable stress.

Created v1.0

By Thibaut Grzelak, Mechanical Analysis Engineer

Piping and pressure
01Calculation inputs
Use the pressure difference between inside and outside.
Value already selected for the material, temperature and applicable design method.

Results are up to date.

03

Results

Metric
Circumferential stress
13.788MPa

Also called hoop stress; it is usually the largest membrane stress.

Longitudinal stress
6.8938MPa

Axial membrane stress for a pipe with closed ends.

von Mises equivalent stress
11.94MPa

Plane-stress state σθ–σz without shear.

Utilization
9.9503%

Ratio σVM/S.

Dm/t ratio
27.575—

Geometric thinness indicator; a larger value better supports the thin-wall assumption.

View calculation detailsFormulas, SI conversion, numerical substitution and resultsOpen ↓

Calculation note

Full calculation details

Adopted range: ri/t > 10, with ri = Do/2 − t (inner radius). This limit is a conservative choice for the membrane model, not a code-compliance check. For a calculated thickness, both the theoretical thickness and the thickness including allowance are checked. Straight circular pipe with closed ends. Uniform positive internal gauge pressure. Wall sufficiently thin to neglect through-thickness stress variation. No local corrosion, ovality, weld, branch, bending, fatigue, shock, temperature or external pressure. This is an educational magnitude check, not a piping-code calculation.

01Formulas and symbols

Formulas used

DmDm = Do − tMean wall diameter
σθσθ = p·Dm/(2t)Circumferential membrane stress
σzσz = p·Dm/(4t)Longitudinal stress in a closed pipe
σVMσVM = √(σθ² − σθσz + σz²)Equivalent plane stress
02Assumptions and limits

Scope of validity

  • Straight circular pipe with closed ends.
  • Uniform positive internal gauge pressure.
  • Wall sufficiently thin to neglect through-thickness stress variation.
  • No local corrosion, ovality, weld, branch, bending, fatigue, shock, temperature or external pressure.
  • This is an educational magnitude check, not a piping-code calculation.
03Validation example

Reference numerical case

  1. p = 10 bar, Do = 114.3 mm, t = 4 mm and S = 120 MPa.
  2. Dm = 110.3 mm.
  3. σθ = 13.7875 MPa and σz = 6.89375 MPa.
  4. σVM = 11.940 MPa and utilization = 9.9503%.
04Direct references