Required theoretical section
Electricity · Industrial electricity
Cable size from maximum voltage drop
Determine the conductor cross-section required to stay below a maximum voltage drop, then verify the drop with the selected preferred section.
Created v1.0
By Thibaut Grzelak, Mechanical Analysis Engineer
Results
Selected preferred section
Calculated voltage difference along the cable.
Voltage drop relative to nominal voltage U.
Estimated voltage at the load after the cable voltage drop.
S = k · ρ · L · I · cosφ / (ΔUmax − k · L · I · X · sinφ)—
L is the one-way distance from source to load, not the total conductor length. Single-phase uses factor 2 for the outgoing and return path; balanced three-phase uses √3. R = ρ / S. X = const. Only voltage drop is checked: ampacity, protection, short-circuit duty, installation method, grouping and code compliance are not verified. Sstd ∈ {1.5 … 630} mm².
01Formulas and symbols
Formulas used
√(1 − cos²φ)sin φU · ΔUmax%ΔUmaxk · ρ · L · I · cosφ / (ΔUmax − k · L · I · X · sinφ)Sreqmin { Sᵢ | Sᵢ ≥ Sreq }Sstdk · L · I · ((ρ / Sstd) cosφ + X sinφ)Voltage drop ΔUU − ΔULoad-end voltage U₂02Assumptions and limits
Scope of validity
- L is the one-way distance from source to load, not the total conductor length.
- Single-phase uses factor 2 for the outgoing and return path; balanced three-phase uses √3.
- R = ρ / S.
- X = const.
- Only voltage drop is checked: ampacity, protection, short-circuit duty, installation method, grouping and code compliance are not verified.
- Sstd ∈ {1.5 … 630} mm².
03Validation example
Reference numerical case
- U = 400 V ; I = 32 A ; L = 50 m ; cos φ = 0.85 ; ρ = 0.01724 Ω·mm²/m ; X = 0.08 Ω/km ; ΔUmax = 3 %
- Sreq ≈ 3.417 mm²
- Sstd = 4 mm²
- ΔU ≈ 10.269 V ; ΔU% ≈ 2.567 % ; U₂ ≈ 389.731 V
04References
Technical references
- IEC 60364-5-52 — Low-voltage electrical installations: selection and erection of wiring systems.