Electricity · Industrial electricity

Three-phase motor current — power, efficiency and power factor

Estimate steady-state three-phase motor current from useful shaft power P₂, line-to-line voltage U, efficiency η and power factor.

Created v1.0

By Thibaut Grzelak, Mechanical Analysis Engineer

Industrial electricity
01Calculation inputsI = P₂ / (√3 · U · η · cosφ)
3φUIMη · cos φP₂P₁ · S · Q
Estimate steady-state three-phase motor current from useful shaft power P₂, line-to-line voltage U, efficiency η and power factor.
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Results

Electrical input power P₁
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Active electrical power absorbed by the motor before losses.

Apparent power S
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Three-phase apparent power corresponding to P₁ and the power factor.

Reactive power Q
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Reactive power associated with apparent power and power factor.

Relation and numerical substitutionI = P₂ / (√3 · U · η · cosφ)

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P₂ is the useful mechanical output power available at the motor shaft. Efficiency η is entered as a percentage and relates P₂ to absorbed electrical power P₁. U is the RMS line-to-line voltage and 0 < cos φ ≤ 1. This is a steady-state calculation: starting current, VFD behavior, cable sizing, voltage drop, protection and code coordination are not sized.

01Formulas and symbols

Formulas used

P₁P₂ / ηElectrical input power from mechanical output and efficiency
SP₁ / cosφApparent power from absorbed active power
QS · √(1 − cos²φ)Reactive power from S and power factor
IS / (√3 · U)Line current in a balanced three-phase system
02Assumptions and limits

Scope of validity

  • P₂ is the useful mechanical output power available at the motor shaft.
  • Efficiency η is entered as a percentage and relates P₂ to absorbed electrical power P₁.
  • U is the RMS line-to-line voltage and 0 < cos φ ≤ 1.
  • This is a steady-state calculation: starting current, VFD behavior, cable sizing, voltage drop, protection and code coordination are not sized.
03Validation example

Reference numerical case

  1. P₂ = 15 kW ; U = 400 V ; η = 90 % ; cos φ = 0.85
  2. P₁ = 15 / 0.90 = 16.667 kW
  3. S = 16.667 / 0.85 = 19.608 kVA
  4. Q = 19.608 × √(1 − 0.85²) ≈ 10.329 kvar
  5. I = 19,607.8 / (√3 × 400) ≈ 28.30 A
04References

Technical references

  1. IEC 60034-1 — Rotating electrical machines: rating and performance.

FAQ

Which power should I enter?

Enter useful mechanical output power P₂, usually the rated shaft power.

What does η mean?

η is motor efficiency: P₂ = η·P₁. The tool accepts efficiency as a percentage.

Why √3?

The √3 factor comes from the balanced three-phase power relation using line-to-line voltage.

Does this include starting current?

No. This is a steady-state current estimate; use manufacturer data for starting current.